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Platform orders index: use BackUrl for current subscription link

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This commit is contained in:
萝卜
2026-03-14 23:12:52 +00:00
parent 918dc8035e
commit 04e49ebbe0
1 changed files with 5 additions and 4 deletions
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9
resources/views/admin/platform_orders/index.blade.php
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@@ -81,10 +81,11 @@
<div class="muted">当前已锁定订阅：</div> <div class="muted">当前已锁定订阅：</div>
<div> <div>
@php @php
$subShowUrl = '/admin/site-subscriptions/' . $currentSubscription->id; // 订阅详情链接：附带 back 回到本页（剔除 back，避免嵌套膨胀），并统一走 BackUrl helper。
$subShowUrl .= '?' . \Illuminate\Support\Arr::query([ $subShowUrl = \App\Support\BackUrl::withBack(
'back' => $selfWithoutBack, '/admin/site-subscriptions/' . $currentSubscription->id,
]); $selfWithoutBack
);
@endphp @endphp
<a class="link" href="{!! $subShowUrl !!}">{{ $currentSubscription->subscription_no }}</a> <a class="link" href="{!! $subShowUrl !!}">{{ $currentSubscription->subscription_no }}</a>
<span class="muted">（订阅ID：{{ $currentSubscription->id }}）</span> <span class="muted">（订阅ID：{{ $currentSubscription->id }}）</span>