Platform orders index: use BackUrl for current subscription link
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@@ -81,10 +81,11 @@
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<div class="muted">当前已锁定订阅:</div>
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<div>
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@php
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$subShowUrl = '/admin/site-subscriptions/' . $currentSubscription->id;
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$subShowUrl .= '?' . \Illuminate\Support\Arr::query([
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'back' => $selfWithoutBack,
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]);
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// 订阅详情链接:附带 back 回到本页(剔除 back,避免嵌套膨胀),并统一走 BackUrl helper。
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$subShowUrl = \App\Support\BackUrl::withBack(
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'/admin/site-subscriptions/' . $currentSubscription->id,
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$selfWithoutBack
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);
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@endphp
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<a class="link" href="{!! $subShowUrl !!}">{{ $currentSubscription->subscription_no }}</a>
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<span class="muted">(订阅ID:{{ $currentSubscription->id }})</span>
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