From 04e49ebbe026a304d2f9b7939e0b00a8f1515261 Mon Sep 17 00:00:00 2001
From: =?UTF-8?q?=E8=90=9D=E5=8D=9C?= <dev@saasshop.local>
Date: Sat, 14 Mar 2026 23:12:52 +0000
Subject: [PATCH] Platform orders index: use BackUrl for current subscription
 link

---
 resources/views/admin/platform_orders/index.blade.php | 9 +++++----
 1 file changed, 5 insertions(+), 4 deletions(-)

diff --git a/resources/views/admin/platform_orders/index.blade.php b/resources/views/admin/platform_orders/index.blade.php
index 4213e19..f1f0fd0 100644
--- a/resources/views/admin/platform_orders/index.blade.php
+++ b/resources/views/admin/platform_orders/index.blade.php
@@ -81,10 +81,11 @@
             <div class="muted">当前已锁定订阅：</div>
             <div>
                 @php
-                    $subShowUrl = '/admin/site-subscriptions/' . $currentSubscription->id;
-                    $subShowUrl .= '?' . \Illuminate\Support\Arr::query([
-                        'back' => $selfWithoutBack,
-                    ]);
+                    // 订阅详情链接：附带 back 回到本页（剔除 back，避免嵌套膨胀），并统一走 BackUrl helper。
+                    $subShowUrl = \App\Support\BackUrl::withBack(
+                        '/admin/site-subscriptions/' . $currentSubscription->id,
+                        $selfWithoutBack
+                    );
                 @endphp
                 <a class="link" href="{!! $subShowUrl !!}">{{ $currentSubscription->subscription_no }}</a>
                 <span class="muted">（订阅ID：{{ $currentSubscription->id }}）</span>