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refactor(platform_orders): use BackUrl::withBack for show/subscription links in index

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萝卜
2026-03-14 19:41:09 +00:00
parent 49784f8ee3
commit 394ff14398
1 changed files with 2 additions and 2 deletions
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4
resources/views/admin/platform_orders/index.blade.php
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@@ -963,7 +963,7 @@
<tr> <tr>
<td>{{ $order->id }}</td> <td>{{ $order->id }}</td>
@php @php
$orderShowUrl = '/admin/platform-orders/' . $order->id . '?' . \Illuminate\Support\Arr::query(['back' => $selfWithoutBack]); $orderShowUrl = \App\Support\BackUrl::withBack('/admin/platform-orders/' . $order->id, $selfWithoutBack);
@endphp @endphp
<td> <td>
<a href="{!! $orderShowUrl !!}">{{ $order->order_no }}</a> <a href="{!! $orderShowUrl !!}">{{ $order->order_no }}</a>
@@ -1084,7 +1084,7 @@
@php @php
// 与本页“订单号 -> 详情页 back”口径一致：订阅详情 back 回到本页自身（剔除 back query，避免嵌套） // 与本页“订单号 -> 详情页 back”口径一致：订阅详情 back 回到本页自身（剔除 back query，避免嵌套）
$subBack = $selfWithoutBack; $subBack = $selfWithoutBack;
$subLink = '/admin/site-subscriptions/' . $order->siteSubscription->id . '?' . \Illuminate\Support\Arr::query(['back' => $subBack]); $subLink = \App\Support\BackUrl::withBack('/admin/site-subscriptions/' . $order->siteSubscription->id, $subBack);
@endphp @endphp
<a class="link" href="{!! $subLink !!}">{{ $order->siteSubscription->subscription_no }}</a> <a class="link" href="{!! $subLink !!}">{{ $order->siteSubscription->subscription_no }}</a>
</div> </div>